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(2*x-(3*x^2))/(5^3) = 0
(2*x-3*x^2)/(5^3) = 0
(2*x-3*x^2)/125 = 0
2*x-3*x^2 = 0
x*(2-3*x) = 0
2-3*x = 0 // - 2
-3*x = -2 // : -3
x = -2/(-3)
x = 2/3
x*(x-2/3) = 0
(x*(x-2/3))/125 = 0
( x-2/3 )
x-2/3 = 0 // + 2/3
x = 2/3
( x )
x = 0
x in { 2/3, 0 }
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